Keath+Torque+and+Rotational+Equilibrium


 * Mass || Actual || Experimental || % Error ||
 * F || 196.7 || 197.25 || .0028 ||
 * E || 206.14 || 205.5 || .0031 ||
 * R || 132.4 || 132 || .0030 ||
 * B || 257.51 || 256.75 || .0029 ||
 * D || 271.02 || 270.5 || .0019 ||

M*24.8=100*20.2 M=81.45 g

1. The closer the force is to the center, the less torque it produces. So a large force would produce a small torque if the lever arm is small and a small force would produce a large torque if the lever arm is large (T=Fr).

2. "Support forces" are not included in calculations because the fulcrum exerts an upward force on the meter stick (canceling it out in the equations).

3. T=Fr therefore the equation would the totaling of the forces and lever arms and setting them equal to each other as such: (0.22)(0.35) = 0.1m + (0.5)(0.12) m = 0.17 kg