Alvarez+lab+21

Average weight of a person = 150 lbs = 68.18 kg Minimum car mass = 500 lbs = 227.27 kg To get the mass overall value 68.18 (20 people per car) + 227.27 = 1590.64 kg Total Mass = 1590.64 kg

Height= 5 meters

U= mgh U= (1590.64)(9.8)(5) U= 77,941.36 J

KE= 1/2mv^2 KE=(1/2)(1590.64)(6.121)^2 KE=29,797.9689 J

v= slope of postion line v= 6.121 m/s

a= slope of velocity line a= 11.23 m/s/s

W= Fd W=(ma)(d) W=(1590.94)(11.23)(15.3) W=273,353.72 J

m= 1590.94 kg

P= mv P= (1590.94)(6.121) P= 9,738.144 (kg*m)/s

Average weight of a person = 150 lbs = 68.18 kg Minimum car mass = 500 lbs = 227.27 kg To get the mass overall value 68.18 (20 people per car) + 227.27 = 1590.64 kg Total Mass = 1590.64 kg

Height= 5 meters

U= mgh U= (1590.64)(9.8)(5) U= 77,941.36 J

KE= 1/2mv^2 KE=(1/2)(1590.64)(15.37)^2 KE=187,883.931 J

v= slope of postion line v= 15.37 m/s

a= slope of velocity line a= 5.29 m/s/s

W= Fd W=(ma)(d) W=(1590.94)(5.29)(7.125) W=59,964.517 J

m= 1590.94 kg

P= mv P= (1590.94)(15.37) P= 24,452.7478 (kg*m)/s

I assumed the mass of the storm runner since i got the average weight of a person and amount of people on the ride. The velocity and acceleration was also estimated because the slope of the line was just the average slope. Finally the distance to find work was estimated and applied to the distance that was in the video, not the whole ride.

My results do seem reasonable, and it makes sense that the KE is greater for the video that didnt show the start compared to the video where the ride started. Overall this way of estimating the properties of the ride are not very accurate but you can get a general understanding of the rides and their characteristics. This was FUN!!!!