Hartranft+Lab+13

Hartranft Lab 13

Hypothesis: Conservation of energy will only apply in elastic collisions. Data/Analysis: KE = 1/2mv^2 P = mv Cup 1 KE = 1/2 (.515)(.67)^2 = .12 J P = (.515)(.67) = .34kg*m/s Cup 2 KE = .08 J P = .29 kg*m/s

% change = 66% Cup 1 Before: KE = .08 J P = .28 kg*m/s After: KE = .01 J P = .10 kg*m/s Cup 2 KE = .01 J P = .10 kg*m/s

% change = 12.5% Cup 1 KE =.21 J P = .66 kgm/s Cup 2 KE =..08 J P = .29 kgm/s

% change = 38% Cup 1 Before: KE = .15 J P =.55 kgm/s After: KE = .04 J P = .3 kgm/s Cup 2 KE = .02 J P = .15 kgm/s

% Change = 26%, 13%