SmithVideoAnalysis(Lab12)

p=mv ke=1/2mv^2 Cart 1 p=.6864*505 p=346.632 ke=1/2*505*.6864^2 ke=118.964 Cart 2 p=.5839*505 p=294.87 ke=1/2*505*.5839^2 ke=86.087 % Conserved 294.87/346.632*100=85% p conserved 86.087/118.964*100=72.4% ke conserved In elastic collisions both momentum and kinetic energy should be conserved. Cart 1 before p=.6465*1015 p=656.1975 ke=1/2*1015*.6465^2 ke=212.1158

Cart 1 after p=.3157*1015 p=320.4355 ke=1/2*1015*.3157^2 ke=50.5807

Cart 2 p=.5620*505 p=283.81 ke=1/2*505*.5620^2 ke=79.7506

% Conserved (283.81+320.4355)/656.1975*100=92% p conserved (50.5807+79.7506)/212.1158*100=61.4% ke conserved

In an elastic collision both ke and p should be conserved.