Roth+Lab+21+Hershey+Park

Assuming the mass is really 10,660 kg as explained in question number 5 of the Storm Runner section of this link [], the following can be calculated: Average velocity=m= 16.35 m/s M= 10,660 kg   Kinetic Energy= (1/2) m v^2 Kinetic Energy = (1/2) (10,660) (16.35^2) Kinetic Energy= 1.4 x 10^6 Joules Momentum=p= mass x velocity Momentum= p = 10,660 (16.35) Momentum= 174,291 kg x m/s

Average Acceleration = slope= 6.469 m/s^2

As long as the mass is really 8255 kg and the height at the top of the hill is really 36.9 m, as specified in question number 1 of the Sidewinder section of the same link that was used above, the following can be calculated: Average X velocity= m= 10.80 m/s M= 8255 kg   Height at top of hill= 36.9 m    G= 9.8m/s^2 U= Potential Energy= mgh Potential Energy= 8255 (9.8) (36.9) Potential Energy = 3.0 x 10^6 Joules K= Kinetic Energy = (1/2) m v^2 Kinetic Energy= (1/2) 8255 (10.80^2) Kinetic Energy = 481,432 Joules Momentum= p= mv   Momentum= 8255 (10.80) Momentum= 89,154 kg x m/s Average X acceleration = 4.783 m/s^2